Hi PeterS, hi guys, it seems my calculations have caused a bit of a stir. I also urge that people don't pass judgement after a quick glance at a few posts on a forum. If you want an honest opinion, why not go to a retailer, that sells multiple systems and let them tell you which one is best. A few troubled cases on a forum (more often than not) don't represent a true demographic of the system's performance.
PeterS, please bear in mind, that those were rushed calculations done after-hours before heading home!
After reading what Micko has said, I checked through my calculations and realised that some of the assumptions were wrong.
I think people on the forum may be a little confused since they haven't seen the actual calculations I used. Also, these figures should be taken in with a grain of salt.
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PV SYSTEM
I assume you've used this 3kW Suntech system with 190 W photovoltaic panels:
http://www.todaesolar.com.au/solar-power-for-homes/3kW-suntech-solar-power-system-special.php
Area_Panel = 1.58 m x 0.808 m = 1.277 m^2
Area_PVArray_Total = 16 x 1.277 = 20.43 m^2
Energy_Produced = 13.5 kWh (data from PeterS)
So you're getting 13.5 kWh from 20.43 m^2 of solar collecting. I.e. For every m^2 of PV installed, you're generating --> 13.5 kWh / 20.43 m^2 = 0.66 kWh/m^2
PV efficiencies are typically 10-20% efficiency (20% being the highest for mono-crystalline in the market). So if we assume it's well ventilated, cool but sunny day, then it'll be operating at fairly good efficiencies. Say... 15%.
So if it's generating 0.66 kWh/m^2, then it's receiving ~ 0.66/0.15 = 4.4 kWh/m^2 (this is total sunlight available on the north face)
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EVACUATED TUBE SYSTEM. This is where some errors in my judgement were made.
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DATA from PeterS
My temperature readings are:
Time Roof Tank Inlet
07:30 28 33 22
08:50 33 31 29
09:45 39 35 34
10:15 39 36 35
10:40 44 38 37
10:55 44 38 38
11:40 44 41 40
14:15 48 43 42
14:35 47 43 42
Initially, I took the TANK readings (as I was in a rush, but this is inaccurate), really it the INLET temperatures (sensor at BOTTOM), that need to be considered, because as we've discussed, the inlet is where the cold water enters, and the INLET will always be lower than the TANK (sensor at the TOP), so it is a conservative measure. Also as Micko pointed out, it is actually 340 L of water, in our "315L" tank.
Energy_Produced (kJ) = mcdT = mass x specific heat of water x difference in temperature
= 340 [L] x 1 [kg/L] x 4.19 [kJ/kgoC] x 20 [oC] = 28,492 kJ.
So say.. 28000 kJ to be CONSERVATIVE.
Now, converting kJ to kWh (for comparison)
1 kJ = 1000 J = 1000 W.s = 1000 [W.s] x 1/1000 [kW/W] x 1/3600 [hr/s] = 1/3600 [kWh]
Energy_Produced [kWh]= 28000 kJ x 1/3600 [kWh/kJ] = 7.778 kWh.
Area_EvacTubes = 2.82 m^2 (previously I took the area of the frames, not the actual collector area)
So for evac tubes your getting: 7.778/2.82 = 2.758 [kWh/m^2]
Given the same conditions with efficiency of ~ 70%, the eastern face should be receiving about 2.758/0.7 = 3.94 kWh/m^2.
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COMPARE EAST vs NORTH INSOLATION
3.94/4.4 = 0.896% or a 10-11% difference between East and North insolation. I.e. More in-line with Micko's values.
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CONCLUSION
To my understanding, there isn't a significant difference between East and North. Your system is still performing optimally, but yes an Eastern face has resulted in minor losses. I am guessing other losses may have arisen out of your leak and the long pipe runs.
Without the intention of offending anyone, even with these calculations... any hydraulic or heating systems has FAR more variables to be considered. Many of which could not be quantified without heavy analysis and computational requirements.
Posted Monday 6 Jun 2011 @ 1:21:59 pm from IP
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